A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
Let the roots are \[\alpha \]and\[\alpha +1\], then, sum of roots\[=2\alpha +1=b\] product of roots \[=\alpha (\alpha +1)=c\] Now, \[{{b}^{2}}-4c={{(2\alpha +1)}^{2}}-4\alpha \,(\alpha +1)\] \[=4{{\alpha }^{2}}+1+4\alpha -4{{\alpha }^{2}}-4\alpha \] \[\therefore \ {{b}^{2}}-4c=1\].
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