A) 125 only
B) 125 and \[-216\]
C) 125 and 215
D) 216 only
Correct Answer: B
Solution :
\[\alpha +{{\alpha }^{2}}=30\]and \[{{\alpha }^{3}}=p\] \[{{\alpha }^{2}}+\alpha -30=0\Rightarrow (\alpha +6)(\alpha -5)=0\]Þ \[\alpha =-6,\,\,5\] \\[p={{\alpha }^{3}}={{(-6)}^{3}}=-216\]and\[p={{(5)}^{3}}\]= 125 \[p=125\]and\[-216\].
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