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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Relation between roots and coefficients

  • question_answer
    If \[1-i\] is a root of the equation \[{{x}^{2}}-ax+b=0\], then \[b=\] [EAMCET  2002]

    A) - 2

    B) - 1

    C) 1

    D) 2

    Correct Answer: D

    Solution :

    \[1-i\] is a root of the equation so \[x=1-i\] \[\Rightarrow (x-1)=-i\]\[\Rightarrow {{(x-1)}^{2}}={{(-i)}^{2}}\,\,\,\,\Rightarrow \,\,{{x}^{2}}-2x+2=0\] By comparison, a = 2, b = 2.


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