A) 1
B) 2
C) 3
D) - 2
Correct Answer: B
Solution :
\[2{{x}^{2}}-(p+1)x+(p-1)=0\] Given \[\alpha -\beta \] = \[\alpha \beta \]Þ \[{{(\alpha +\beta )}^{2}}-4\alpha \beta \] = \[{{\alpha }^{2}}{{\beta }^{2}}\] Þ\[\frac{{{(p-1)}^{2}}}{4}=\frac{{{(p+1)}^{2}}}{4}-\frac{4(p-1)}{2}\] Þ \[2(p-1)=p\Rightarrow p=2\].
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