A) \[\frac{c-a}{c+a}\]
B) \[\frac{a-b}{a+b}\]
C) \[\frac{b-c}{b+c}\]
D) None of these
Correct Answer: C
Solution :
\[\tan \frac{B-C}{2}=x\cot \frac{A}{2}\Rightarrow x=\frac{b-c}{b+c}\].
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