A) Right angled
B) Right angled isosceles
C) Isosceles
D) Obtuse angled
Correct Answer: D
Solution :
\[\cos C=\frac{{{a}^{2}}+{{b}^{2}}-{{c}^{2}}}{2ab}\] Þ \[\frac{\sqrt{3}}{2}=\frac{{{(47)}^{2}}+{{(94)}^{2}}-{{c}^{2}}}{2\times 47\times 94}\]\[\Rightarrow c=58.24\] \[\angle B={{124}^{o}}\]. Hence obtuse angled triangle.
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