A) \[\sqrt{3}\]
B) \[\sqrt{6}\]
C) \[\sqrt{9}\]
D) \[1+\sqrt{2}\]
Correct Answer: B
Solution :
\[B={{60}^{o}}\], \[C={{75}^{o}}\] Þ \[A={{180}^{o}}-{{60}^{o}}-{{75}^{o}}={{45}^{o}}\] Now\[\frac{b}{\sin B}=\frac{a}{\sin A}\]Þ \[\frac{b}{\sin {{60}^{o}}}=\frac{2}{\sin {{45}^{o}}}\Rightarrow b=\sqrt{6}\].
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