A) {3}
B) \[\{7p-3:p\in Z\}\]
C) \[\{7p+3:p\in Z\}\]
D) None of these
Correct Answer: C
Solution :
\[x\equiv 3\,(\bmod \,7)\] Þ \[x-3=7p,\,(p\in z)\] \[\Rightarrow \] \[x=7p+3,\,p\in z\] i.e., \[\{7p+3\,:\,p\in z)\].
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