A) \[2(y-1)=3(x+1)\]
B) \[3(y-1)=-\ 2(x+1)\]
C) \[y-1=2(x+1)\]
D) \[3(y-1)=x+1\]
Correct Answer: A
Solution :
The gradient of line \[2x+3y+4=0\]is \[-\frac{2}{3}\]. Now the equation of line passing through (-1,1) is \[y-1=m(x+1),\] but \[m=-\frac{1}{-2/3}=\frac{3}{2}\]. Therefore, required equation is\[2(y-1)=3(x+1)\].
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