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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of line, which bisect the line joining two points (2, -19) and (6, 1) and perpendicular to the line joining two points (-1, 3) and (5, - 1), is           [RPET 1987]

    A) \[3x-2y=30\]                           

    B) \[2x-y-3=0\]

    C) \[2x+3y=20\]                         

    D) None of these

    Correct Answer: A

    Solution :

    Midpoint \[\equiv (4,-\,9);\] Slope \[=\frac{-1}{\frac{3+1}{-1-5}}=\frac{3}{2}\]                    Hence the required line is\[3x-2y=30\].


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