JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    A line perpendicular to the line \[ax+by+c=0\] and passes through \[(a,\ b).\] The equation of the line is  [RPET 1988; MP PET 1995]

    A)            \[bx-ay+({{a}^{2}}-{{b}^{2}})=0\]                                 

    B)            \[bx-ay-({{a}^{2}}-{{b}^{2}})=0\]

    C)            \[bx-ay=0\]                              

    D)            None of these

    Correct Answer: C

    Solution :

               The required equation of line which passes through (a,b) and gradient \[\frac{b}{a}\] is, \[y-b=\frac{b}{a}(x-a)\] \[\Rightarrow bx-ay=0\].


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