JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equations of the lines through the point of intersection of the lines \[x-y+1=0\] and \[2x-3y+5=0\] and whose distance from the point (3, 2) is \[\frac{7}{5},\]is                               [IIT 1963]

    A)            \[3x-4y-6=0\] and \[4x+3y+1=0\]

    B)            \[3x-4y+6=0\] and \[4x-3y-1=0\]

    C)            \[3x-4y+6=0\] and \[4x-3y+1=0\]

    D)            None of these                          

    Correct Answer: C

    Solution :

               Point of intersection is (2, 3). Therefore, the equation of line passing through (2, 3) is                                 \[y-3=m\,(x-2)\]                                     ??(i)                    or         \[mx-y-(2m-3)=0\].                    According to the condition,                    \[\frac{3m-2-(2m-3)}{\sqrt{1+{{m}^{2}}}}=\frac{7}{5}\Rightarrow m=\frac{3}{4},\frac{4}{3}\]                    Hence the equations are \[3x-4y+6=0\] and \[4x-3y+1=0\].


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