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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of straight line passing through the intersection of the lines \[x-2y=1\] and \[x+3y=2\] and parallel to \[3x+4y=0\] is [MP PET 2000]

    A)            \[3x+4y+5=0\]                      

    B)            \[3x+4y-10=0\]

    C)            \[3x+4y-5=0\]                        

    D)            \[3x+4y+6=0\]

    Correct Answer: C

    Solution :

               The intersection point of lines \[x-2y=1\] and \[x+3y=2\] is \[\left( \frac{7}{5},\,\frac{1}{5} \right)\] and the slope of required line \[=-\frac{3}{4}\]                    \ Equation of required line is \[y-\frac{1}{5}=\frac{-3}{4}\left( x-\frac{7}{5} \right)\]                    Þ\[\frac{3x}{4}+y=\frac{21}{20}+\frac{1}{5}\]Þ\[3x+4y=5\]Þ\[3x+4y-5=0\].


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