2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Straight Line

JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    Equation of a line passing through the point of intersection of lines \[2x-3y+4=0,\] \[3x+4y-5=0\] and perpendicular to \[6x-7y+3=0,\] then its equation is                                           [RPET 2000]

    A)            \[119x+102y+125=0\]        

    B)            \[119x+102y=125\]              

    C)            \[119x-102y=125\]                

    D)            None of these

    Correct Answer: B

    Solution :

               The point of intersection of lines \[2x-3y+4=0\] and \[3x+4y-5=0\] is \[\left( \frac{-2}{34},\,\frac{22}{17} \right)\]                    The slope of required line \[=\frac{-7}{6}\]                    \  Equation of required line is \[y-\frac{22}{17}=\frac{-7}{6}\left( x+\frac{2}{34} \right)\]                    Þ \[119x+102y=125\].


You need to login to perform this action.
You will be redirected in 3 sec spinner