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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    Equation to the straight line cutting off an intercept 2 from the negative direction of the axis of y and inclined at 30o to the positive direction of axis of x, is        [MP PET 2003]

    A)            \[y+x-\sqrt{3}=0\]                 

    B)            \[y-x+2=0\]

    C)            \[y-\sqrt{3}\,x-2=0\]               

    D)            \[\sqrt{3}y-x+2\sqrt{3}=0\]

    Correct Answer: D

    Solution :

               \[y=mx+c\];  \[\because \] \[m=\tan 30{}^\circ \]\[=\frac{1}{\sqrt{3}}\]; \[c=-2\]                    \[\therefore \]\[y=\frac{x}{\sqrt{3}}-2\] Þ \[\sqrt{3}y-x+2\sqrt{3}=0\].


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