A) \[6x+y-19=0\]
B) \[y=7\]
C) \[6x+2y-19=0\]
D) \[x+2y-7=0\]
Correct Answer: A
Solution :
Equation of the line passing through \[(-4,\,6)\] and \[(8,\,8)\] is \[y-6=\left( \frac{8-6}{8+4} \right)\,(x+4)\]Þ \[y-6=\frac{2}{12}(x+4)\] Þ \[6y-36=x+4\] Þ \[6y-x-40=0\] ??(i) Now equation of any line perpendicular to it is \[6x+y+\lambda =0\] ??(ii) This line passes through the mid point of \[(-4,\,6)\] and \[(8,\,8)\] i.e., \[(2,\,7)\]Þ \[6\times 2+7+\lambda =0\] Þ \[19+\lambda =0\Rightarrow \lambda =-19\] From (ii) the equation of required line is \[6x+y-19=0\].
You need to login to perform this action.
You will be redirected in
3 sec
