A) (5, 5), (- 1, - 1)
B) (7, 5), (- 1, - 1)
C) (5, 7), (- 1, - 1)
D) (7, 5), (1, 1)
Correct Answer: B
Solution :
The equation of line passes through (3, 2) and of slope \[\frac{3}{4}\] is \[3x-4y-1=0\] Let the point be \[(h,k)\]then \[3h-4k-1=0\] ??(i) and \[{{(h-3)}^{2}}+{{(y-2)}^{2}}={{5}^{2}}\] ??(ii) On solving the equations, we get \[h=-1,\,7\] and \[k=-1,5\]. Hence points are (?1, ?1) and (7, 5).
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