A) In A.P.
B) In H.P.
C) In G.P.
D) None of these
Correct Answer: A
Solution :
\[ax+by+c=0\] is always through \[(1,\,-2)\]. \ \[a-2b+c=0\] Þ \[2b=a+c\] Therefore, a, b and c are in A.P.
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