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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    The roots of the equation \[{{x}^{2/3}}+{{x}^{1/3}}-2=0\] are [UPSEAT 2004]

    A) 1, 4

    B) \[1,-4\]

    C) \[1,-8\]

    D) 1, 8

    Correct Answer: C

    Solution :

    \[{{x}^{2/3}}+{{x}^{1/3}}-2=0\]Þ \[{{({{x}^{1/3}})}^{2}}+1({{x}^{1/3}})-2=0\] Let \[a={{x}^{1/3}},\] then \[{{a}^{2}}+a-2=0\]Þ \[a=1,-2\] Hence\[x=1,-8\](by \[a={{x}^{1/3}}\]).


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