A) \[a\in [2,\,8]\]
B) \[a\in [-2,\,8]\]
C) \[a\in (2,\,8)\]
D) \[a\in (-2,\,8)\]
Correct Answer: B
Solution :
Since the roots \[{{x}^{2}}-8x+{{a}^{2}}-6a=0\] are real. \ \[64-4({{a}^{2}}-6a)\ge 0\]or \[{{a}^{2}}-6a-16\le 0\] Þ \[a\in [-2,8]\]
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