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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    The value of k for which the equation\[(k-2){{x}^{2}}+8x+k+4=0\] has both real, distinct and negative is[Orissa JEE 2002]

    A) 0

    B) 2

    C) 3

    D) - 4

    Correct Answer: C

    Solution :

    From options put \[k=3\Rightarrow {{x}^{2}}+8x+7=0\] Þ \[(x+1)(x+7)=0\]\[\Rightarrow x=-1,\,-7\] means for k = 3 roots are negative.


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