A) \[1,\frac{1}{2},\frac{1}{4}\]
B) 2, 4, 8
C) 3, 6, 12
D) None of these
Correct Answer: A
Solution :
Let the roots be\[\frac{\alpha }{\beta },\alpha ,\alpha \beta ,\beta \ne 0\]. Then the product of roots is \[{{\alpha }^{3}}=-\frac{-1}{8}=\frac{1}{8}\Rightarrow \,\,\alpha =\frac{1}{2}\] and hence \[\beta =\frac{1}{2}\], so roots are \[1,\frac{1}{2},\frac{1}{4}\] Trick: By inspection, we get the numbers \[1,\frac{1}{2},\frac{1}{4}\] satisfying the given equation.
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