A) \[n\pi +\frac{\pi }{4}\]
B) \[2n\pi \pm \frac{\pi }{4}\]
C) \[n\pi -\frac{\pi }{4}\]
D) \[2n\pi \pm \frac{\pi }{6}\]
Correct Answer: A
Solution :
We have \[\frac{\pi }{4}\cot \theta =\frac{\pi }{2}-\frac{\pi }{4}\tan \theta \]\[\Rightarrow \tan \theta +\cot \theta =2\] \[\Rightarrow \] \[\sin 2\theta =1=\sin \frac{\pi }{2}\Rightarrow \theta =n\pi +\frac{\pi }{4}\].
You need to login to perform this action.
You will be redirected in
3 sec
