JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    If \[\left| \,\begin{matrix}    \cos (A+B) & -\sin (A+B) & \cos 2B  \\    \sin A & \cos A & \sin B  \\    -\cos A & \sin A & \cos B  \\ \end{matrix}\, \right|=0\], then B = [EAMCET 2003]

    A) \[(2n+1)\frac{\pi }{2}\]

    B) \[n\pi \]

    C) \[(2n+1)\frac{\pi }{2}\]

    D) \[2n\pi \]

    Correct Answer: A

    Solution :

    On expanding determinant,          \[{{\cos }^{2}}(A+B)+{{\sin }^{2}}(A+B)+\cos 2B=0\]         \[1+\cos 2B=0\]or \[\cos 2B=\cos \pi \] or   \[2B=2n\pi +\pi \] or \[B=(2n+1)\frac{\pi }{2},\,\,n\in Z.\]


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