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JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    The number of values of \[\theta \] in [0, 2p] satisfying the equation \[2{{\sin }^{2}}\theta =4+3\]\[\cos \theta \]are [MP PET 1989]

    A) 0

    B) 1

    C) 2

    D) 3

    Correct Answer: A

    Solution :

    \[2-2{{\cos }^{2}}\theta =4+3\cos \theta \]\[\Rightarrow \] \[2{{\cos }^{2}}\theta +3\cos \theta +2=0\] \[\Rightarrow \] \[\cos \theta =\frac{-3\pm \sqrt{9-16}}{4}\], which is imaginary, hence no solution.


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