JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    If \[5\cos 2\theta +2{{\cos }^{2}}\frac{\theta }{2}+1=0,-\pi <\theta <\pi \], then \[\theta =\]  [Roorkee 1984]

    A) \[\frac{\pi }{3}\]

    B) \[\frac{\pi }{3},{{\cos }^{-1}}\frac{3}{5}\]

    C) \[{{\cos }^{-1}}\frac{3}{5}\]

    D) \[\frac{\pi }{3},\pi -{{\cos }^{-1}}\frac{3}{5}\]

    Correct Answer: D

    Solution :

    \[5\cos 2\theta +2{{\cos }^{2}}\frac{\theta }{2}+1=0\] \[\Rightarrow \]  \[5(2{{\cos }^{2}}\theta -1)+(1+\cos \theta )+1=0\] \[\Rightarrow \]   \[10{{\cos }^{2}}\theta +\cos \theta -3=0\] \[\Rightarrow \]   \[(5\cos \theta +3)\,(2\cos \theta -1)=0\] \[\Rightarrow \]  \[\cos \theta =\frac{1}{2},\,\cos \theta =-\frac{3}{5}\Rightarrow \theta =\frac{\pi }{3},\,\pi -{{\cos }^{-1}}\left( \frac{3}{5} \right)\].


You need to login to perform this action.
You will be redirected in 3 sec spinner