A) \[n\pi +{{(-1)}^{n}}\frac{\pi }{6}\]
B) \[n\pi +\frac{\pi }{6}\]
C) \[2n\pi \pm \frac{\pi }{6}\]
D) None of these
Correct Answer: D
Solution :
\[\sin \theta =-\frac{1}{2}=\sin \left( -\frac{\pi }{6} \right)=\sin \text{ }\left( \pi +\frac{\pi }{6} \right)\] \[\tan \theta =\frac{1}{\sqrt{3}}=\tan \left( \frac{\pi }{6} \right)=\tan \left( \pi +\frac{\pi }{6} \right)\Rightarrow \theta =\left( \pi +\frac{\pi }{6} \right)\] Hence general value of \[\theta \] is \[2n\pi +\frac{7\pi }{6}\].
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