A) \[n\pi \]
B) \[2n\pi +\frac{3\pi }{4}\]
C) \[2n\pi \]
D) \[(2n+1)\,\pi \]
Correct Answer: B
Solution :
\[\sin x\frac{1}{\sqrt{2}}-\cos x\frac{1}{\sqrt{2}}=1\Rightarrow \cos \left( x+\frac{\pi }{4} \right)=-1\] Þ \[x+\frac{\pi }{4}=2n\pi \pm \pi \Rightarrow 2n\pi +\frac{3\pi }{4}\text{or}\,\,2n\pi -\frac{5\pi }{4}\] .
You need to login to perform this action.
You will be redirected in
3 sec
