question_answer

PQ is a tower standing on a horizontal plane, Q being the foot of the tower. A and B are two points on the plane such that\[\angle \text{BQP}\] is\[\text{9}0{}^\circ \], AB = 4 m. If \[\cot (\angle PAQ)=\frac{3}{10}\]and\[\cot (\angle PBQ)=\frac{1}{2}\], find the height of the tower.

A) 10m                                      

B) 15m

C) 18m                      

D)        20m