question_answer

A source of light is placed at a distance 1 m from a photocell and cut off potential is found to be \[{{V}_{0}}\] If the distance is doubled, then cut-off potential will be                                  

A)  \[\text{2}{{\text{V}}_{0}}\]                       

B)        \[{{\text{V}}_{0}}/\text{2}\]          

C)  \[{{\text{V}}_{0}}\]                         

D)         \[{{\text{V}}_{0}}/\text{2}\]