A) \[1.05\,eV\]
B) \[1.5\,eV\]
C) \[2.05\,eV\]
D) \[2.5\,eV\]
Correct Answer: A
Solution :
\[Z=\left( \frac{{{\lambda }_{0}}-{{\lambda }_{1}}}{{{\lambda }_{0}}-{{\lambda }_{2}}} \right)\frac{{{\lambda }_{2}}}{\lambda }\] \[\Rightarrow \] \[{{\lambda }_{0}}=11\times 8\times {{10}^{-7}}m\] \[W=\frac{hc}{{{\lambda }_{0}}}\] \[=\frac{6\cdot 6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{11.8\times {{10}^{-7}}\times 1\cdot 6\times {{10}^{-19}}}\] \[\mathbf{=1}\mathbf{.05}\,\,\mathbf{eV}\]
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