A) N
B) 2N
C) - N
D) None of these
Correct Answer: A
Solution :
The cofactors of \[N=\left[ \begin{matrix} -4 & -3 & -3 \\ 1 & 0 & 1 \\ 4 & 4 & 3 \\ \end{matrix} \right]\] are\[{{c}_{11}}=-4,\,{{c}_{12}}=1,\,{{c}_{13}}=4\]; \[{{c}_{21}}=-3,\,{{c}_{22}}=0,\,{{c}_{23}}=4\] \[{{c}_{31}}=-3,\,{{c}_{32}}=1,\,{{c}_{33}}=3\] \[\therefore \] \[adj\,N=\left[ \begin{matrix} -4 & -3 & -3 \\ 1 & 0 & 1 \\ 4 & 4 & 3 \\ \end{matrix} \right]=N\].
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