JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Special types of matrices, Transpose, Adjoint and Inverse of matrices

  • question_answer
    The element of second row and third column in the inverse of  \[\left[ \begin{matrix}    1 & 2 & 1  \\    2 & 1 & 0  \\    -1 & 0 & 1  \\ \end{matrix} \right]\] is [MP PET 1992]

    A) - 2

    B) - 1

    C) 1

    D) 2

    Correct Answer: B

    Solution :

    In \[{{A}^{-1}},\] the element of 2nd row and 3rd column is the \[{{c}_{32}}\] element of the matrix \[({{c}_{ij}})\] of cofactors of element of \[Adj\,(A)=\left[ \begin{matrix}    1 & -2 & 4  \\    4 & 1 & -2  \\    -2 & 4 & 1  \\ \end{matrix} \right]\], (due to transposition) divided by \[\Delta =\,|A|\,=-2\]. \[\therefore \] Required element =\[\frac{{{(-1)}^{3+2}}{{M}_{32}}}{-2}\,\text{  }=\frac{-(-2)}{-2}=-1\], where \[{{M}_{32}}=\]minor of \[{{c}_{32}}\] in \[Adj\,(A)=\left[ \begin{matrix}    12 & -5  \\    -7 & 3  \\ \end{matrix} \right]\].


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