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JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Special types of matrices, Transpose, Adjoint and Inverse of matrices

  • question_answer
    \[A=\left[ \begin{matrix}    0 & 3  \\    2 & 0  \\ \end{matrix} \right]\]and \[{{A}^{-1}}=\lambda (adj(A)),\]then \[\lambda =\] [UPSEAT 2002]

    A) \[\frac{-1}{6}\]

    B) \[\frac{1}{3}\]

    C) \[\frac{-1}{3}\]

    D) \[\frac{1}{6}\]

    Correct Answer: A

    Solution :

    \[K={{[|A|]}^{-1}}=\frac{-1}{6}\].


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