A) \[\lambda \,adjX\]
B) \[{{\lambda }^{3}}adj\,X\]
C) \[{{\lambda }^{2}}adj\,X\]
D) \[{{\lambda }^{4}}adj\,X\]
Correct Answer: C
Solution :
By fundamental property, \[adj(\lambda X)={{\lambda }^{n-1}}(adj\,X)\]. Here \[n=3\] \\[adj(\lambda X)={{\lambda }^{3-1}}(adj\,X)\] \[adj(\lambda X)={{\lambda }^{2}}(adj\,X)\].
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