A) \[\cos \frac{\pi }{2}+i\sin \frac{\pi }{2}\]
B) \[\cos \frac{\pi }{2}-i\sin \frac{\pi }{2}\]
C) \[\sin \frac{\pi }{2}+i\cos \frac{\pi }{2}\]
D) None of these
Correct Answer: B
Solution :
\[\frac{1-i}{1+i}=\frac{(1-i)(1-i)}{(1+i)(1-i)}=\frac{1+{{(i)}^{2}}-2i}{1+1}=-i\] which can be written as \[\cos \frac{\pi }{2}-i\]\[\sin \frac{\pi }{2}\]
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