10th Class Mathematics Statistics Question Bank Statistics and Probability

  • question_answer
    The geometric mean of two numbers a and b is 8 and their harmonic mean is 6.4. The numbers are

    A)  2.8                        

    B)         4.16  

    C)  4.8                        

    D)         2.16

    Correct Answer: B

    Solution :

     By hypothesis, \[\sqrt{ab}=8\] or            \[ab=64\]                            ??(i) Now      \[\frac{2ab}{a+b}=6.4\] From equation (i)                 \[2\times 64=6.4\,(a+b)\] or            \[a+b=20\]                          ??(ii) or            \[b=20-a\] Substituting the value of b in equation (i), we get                 \[a(20-a)=64\] or            \[{{a}^{2}}-20a+64=0\] or            \[(a-16)\,(a-4)=0\] \[\therefore \]  \[{{a}^{2}}=16\] or \[a=4\] From equation (ii)                 \[b=20-16\] or            \[20-4=4\] or \[16\] Hence the numbers are \[4,16\].


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