question_answer

The total number of isomers formed by \[{{C}_{5}}{{H}_{10}}\] is [Bihar MEE 1996]

A) 2

B) 3

C) 4

D) 5

E) None of these

Correct Answer: D

Solution :

  (1) \[\underset{\text{Pent-1-ene}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}}}\,\] (2) \[\underset{\text{Pent-2-ene}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH=CH-C{{H}_{3}}}}\,\] (3) \[\underset{\text{2}-\text{Methyl}-\text{1}-\text{butene}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,}{\mathop{C\,\,=\,\,}}\,}}\,C{{H}_{2}}}}\,\] (4) \[\underset{\text{2}-\text{Methyl}-\text{2}-\text{butene}}{\mathop{C{{H}_{3}}-CH=\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{C\,\,\,\,\,}}\,}}\,-C{{H}_{3}}}}\,\] (5)