A) \[{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[CC{{l}_{2}}{{F}_{2}}\]
D) \[C{{H}_{3}}CHOH{{C}_{2}}{{H}_{5}}\]
Correct Answer: D
Solution :
\[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}}}{\mathop{\underset{\,\,\,\,\,|}{\mathop{\overset{\,\,\,\,\,\,\,\,\,\,\,\,OH}{\mathop{\overset{\,\,\,\,\,\,\,\,|*}{\mathop{C{{H}_{3}}-C-H}}\,}}\,}}\,}}\,\] In this structure chiral carbon is present that is why it is optically active.
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