A) \[a=1,\,b=2\]
B) \[a=2,\,b=-4\]
C) \[a=2,\,b=4\]
D) \[a=-2,\,b=4\]
Correct Answer: C
Solution :
\[\frac{2\times 5+1(a)}{2+1}=4\Rightarrow a=2\] and \[\frac{2\times 7+1(b)}{2+1}=6\Rightarrow b=4\].
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