A) 1
B) 0
C) -1
D) 2
Correct Answer: B
Solution :
\[a+b-2c=0\] \[2a-3b+c=0\] \[a-5b+4c=\alpha \] System is consistent, if \[D=\left| \,\begin{matrix} 1 & 1 & -2 \\ 2 & -3 & 1 \\ 1 & -5 & 4 \\ \end{matrix}\, \right|\]=0 and \[{{D}_{1}}=\left| \,\begin{matrix} 0 & 1 & -2 \\ 0 & -3 & 1 \\ \alpha & -5 & 4 \\ \end{matrix}\, \right|\]= 0 and \[{{D}_{2}}\] also zero. Hence, value of \[\alpha \] is zero.
You need to login to perform this action.
You will be redirected in
3 sec
