A) \[x-\sqrt{3}y=0\]
B) \[x+\sqrt{3}y=0\]
C) \[\sqrt{3}x+y=0\]
D) \[\sqrt{3}x-y=0\]
Correct Answer: D
Solution :
Slope is given by \[\frac{dy}{dx}=\sqrt{3}\,\,\Rightarrow \,\int_{{}}^{{}}{dy}=\sqrt{3}\int_{{}}^{{}}{dx}\] \[\Rightarrow \,\,\sqrt{3}x-y+c=0\] This passes through (0, 0), so c = 0 Hence the required locus is \[\sqrt{3}x-y=0\].
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