A) \[{{x}^{2}}+8x+4y-20=0\]
B) \[{{x}^{2}}-8x-4y+20=0\]
C) \[{{y}^{2}}-4y-8x+20=0\]
D) None of these
Correct Answer: B
Solution :
\[{{(x-4)}^{2}}+{{(y-2)}^{2}}={{y}^{2}}\,\,\Rightarrow \,\,{{x}^{2}}-8x-4y+20=0\].
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