A) \[{{30}^{o}}\]
B) \[{{40}^{o}}\]
C) \[{{20}^{o}}\]
D) \[{{10}^{o}}\]
Correct Answer: B
Solution :
Given that the angles of the triangle are \[(x+{{10}^{o}}),\,(x+{{40}^{o}})\] and \[(2x-{{30}^{o}})\]. Sum of the angles of a triangle \[={{180}^{o}}\] \[\Rightarrow \]\[x+{{10}^{o}}+x+{{40}^{o}}+2x-{{30}^{o}}={{180}^{o}}\] \[\Rightarrow \] \[4x={{160}^{o}}\] \[\Rightarrow \] \[x={{40}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
