A) \[{{110}^{o}}\]
B) \[{{35}^{o}}\]
C) \[{{140}^{o}}\]
D) \[{{155}^{o}}\]
Correct Answer: A
Solution :
Given, AB = AC \[\Rightarrow \] \[\angle ABC=\angle ACB\] Also \[\angle OBC=\angle OCA\] \[\Rightarrow \]OB and OC are angular bisectors \[\therefore \] \[\angle BOC={{90}^{o}}+\frac{\angle A}{2}\] \[={{90}^{o}}+\frac{{{40}^{o}}}{2}={{90}^{o}}+{{20}^{o}}={{110}^{o}}\]You need to login to perform this action.
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