A) \[\tan A\]
B) \[\tan 2A\]
C) \[\cot A\]
D) \[\cot 2A\]
Correct Answer: D
Solution :
\[\frac{1}{\tan 3A-\tan A}-\frac{1}{\cot 3A-\cot A}\] =\[\frac{1}{\tan 3A-\tan A}+\frac{\tan A\tan 3A}{\tan 3A-\tan A}=\frac{1}{\tan 2A}=\cot 2A\].
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