A) \[\cos \theta \]
B) \[\sin \theta \]
C) \[2\cos \theta \]
D) \[2\sin \theta \]
Correct Answer: C
Solution :
\[\sqrt{2+\sqrt{2+2\cos 4\theta }}\]=\[\sqrt{2+\sqrt{2.2{{\cos }^{2}}2\theta }}\] \[=\sqrt{2+2\cos 2\theta }=\sqrt{4{{\cos }^{2}}\theta }=2\cos \theta \].
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