A) \[\frac{1}{3}\]
B) \[\sqrt{3}-2\]
C) \[2-\sqrt{3}\]
D) None of these
Correct Answer: C
Solution :
\[\tan {{15}^{o}}=\tan ({{45}^{o}}-{{30}^{o}})\] \[=\frac{1-1/\sqrt{3}}{1+1/\sqrt{3}}=\frac{\sqrt{3}-1}{\sqrt{3}+1}\times \frac{\sqrt{3}-1}{\sqrt{3}-1}=2-\sqrt{3}\].
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