10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    \[\tan \theta (1-co{{t}^{2}}\theta )\] is equal to

    A) \[\cot \theta (1-ta{{n}^{2}}\theta )\]

    B) \[\cot \theta (ta{{n}^{2}}\theta -1)\]

    C) \[\cot \theta ta{{n}^{2}}\theta \]

    D) \[tan\theta {{\operatorname{cosec}}^{2}}\theta \]

    Correct Answer: B

    Solution :

     \[\tan \theta \,(1-{{\cot }^{2}}\theta )=\tan \theta \left( 1-\frac{1}{{{\tan }^{2}}\theta } \right)\] \[=\tan \theta \frac{({{\tan }^{2}}\theta -1)}{{{\tan }^{2}}\theta }\] \[=\frac{({{\tan }^{2}}\theta -1)}{\tan \theta }\] \[=\cot \theta \,({{\tan }^{2}}\theta -1)\]


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