question_answer

If \[\beta \] is acute and \[\sin \beta =\frac{4}{5}\] the value of \[\frac{1-\frac{\sin \beta }{\tan \beta }}{1+\frac{\sin \beta }{\tan \beta }}\]

A) \[\frac{1}{4}\]

B) \[\frac{3}{4}\]

C) \[\frac{3}{5}\]

D) \[\frac{5}{3}\]